若（3x-y+5）²+√2x-y+3=0,求x-y的值

若（3x-y+5）²+√2x-y+3=0,求x-y的值
若（3x-y+5）²+√2x-y+3=0,求x-y的值

若（3x-y+5）²+√2x-y+3=0,求x-y的值
（3x-y+5）²+√2x-y+3=0,
3x-y+5 =0 ①
2x-y+3 = 0 ②
①-② x+2 = 0
x = -2
y = 3x+5 = -6+5 = -1
x-y的值
= -2 +1
= -1