sat2 Barron 英文的物理题A 3-centimeter-tall candle is placed in front of a concave spherical mirror.An inverted image,half the size of the original,is observed on a screen.Where,relative to the mirror,must the candle have been placed?答案是b

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sat2 Barron 英文的物理题A 3-centimeter-tall candle is placed in front of a concave spherical mirror.An inverted image,half the size of the original,is observed on a screen.Where,relative to the mirror,must the candle have been placed?答案是b

sat2 Barron 英文的物理题A 3-centimeter-tall candle is placed in front of a concave spherical mirror.An inverted image,half the size of the original,is observed on a screen.Where,relative to the mirror,must the candle have been placed?答案是b
sat2 Barron 英文的物理题
A 3-centimeter-tall candle is placed in front of a concave spherical mirror.An inverted image,half the size of the original,is observed on a screen.Where,relative to the mirror,must the candle have been placed?答案是beyond 2f.我想知道这道题里怎么用造镜者公式,就是1/di＋1/do＝1/f.

sat2 Barron 英文的物理题A 3-centimeter-tall candle is placed in front of a concave spherical mirror.An inverted image,half the size of the original,is observed on a screen.Where,relative to the mirror,must the candle have been placed?答案是b
lz题目中的concave mirror是凹面镜,凹面镜的成像情况与凸透镜成像情况完全一致.
凹面镜成像公式为:1/u+1/v=1/f=2/R(1)式中物距u为物体至凹面镜顶点的距离,像距v为所成的像至凹面镜顶点的距离,f为凹面镜焦距,R为凹面镜曲率半径,凹面镜的焦距与曲率半径的关系为f=R/2.
像的大小是物的一半,像距即为物距的一半,所以比有物距大于两倍焦距.
lz只要记住凹面镜成像规律与凸透镜成像规律一样就可以了.
当然画图也是可以解决的.

为什么一定呀一定用 那公式呢，画一下图就可以求啦！

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